Objective: To derive expressions for the Total Energy and Binding Energy of an orbiting satellite.
Total Energy of a Satellite
The total energy of a satellite in its orbit is the sum of its Potential Energy (P.E.) and Kinetic Energy (K.E.).
$$E = U + K.E.$$
Where,
- $M$ = Mass of Earth
- $m$ = Mass of satellite
- $R$ = Radius of Earth
- $h$ = Height of satellite above Earth's surface
- $r = R+h$ = Radius of orbit
1. Potential Energy of Satellite
The gravitational potential energy of a satellite revolving around the Earth in a circular orbit is:
$$ U = -\frac{GMm}{R+h} $$or
$$U = -\frac{GMm}{r} $$2. Kinetic Energy of Satellite
The kinetic energy of the satellite is:
$$ K.E.=\frac{1}{2}mv_0^2 $$where $v_0$ is the orbital velocity.
Since the satellite moves in a circular orbit,
Centripetal Force = Gravitational Forceor
$$ mv_0^2=\frac{GMm}{R+h} $$Substituting in the kinetic energy equation,
$$K.E. = \frac{1}{2} \left( \frac{GMm}{R+h} \right) $$or
$$ K.E. = \frac{GMm}{2r} $$3. Total Energy of Satellite
$$ E = U + K.E. $$Since
$$ r=R+h $$therefore,
$$ E = -\frac{GMm}{2r} $$Significance
Significance
If E<0, the satellite remains bound to Earth.
If E=0, the satellite escapes Earth's gravitational field.
If E>0, the satellite moves away from Earth.
Binding Energy of a Satellite
Definition
The minimum energy required by a satellite to escape from its orbit to infinity is called the Binding Energy.
Energy of satellite in orbit:
$$ E=-\frac{GMm}{2r} $$At infinity,
$$ E_{\infty}=0 $$Therefore,
$$ B.E. = 0-E $$or
$$ B.E. = \frac{GMm}{2(R+h)} $$Important Facts
If K.E. of a Satellite is Doubled
Original total energy:
$$E = \frac{GMm}{2(R+h)} - \frac{GMm}{R+h} $$If kinetic energy is doubled,
$$ K.E.' = 2(K.E.) = \frac{GMm}{R+h} $$Then,
$$ E' = K.E.' + P.E. $$Hence, the satellite escapes from Earth's gravitational field.
Important Relations
$$K.E.=-E $$Frequently Asked Questions (FAQ)
Q1. Why is the total energy of a satellite negative?
Because the satellite is gravitationally bound to the Earth.
$E=-\frac{GMm}{2r} $A negative total energy indicates a bound system.
Q2. What is the relation between K.E. and P.E.?
$ K.E.=-\frac{U}{2} $Q3. What is the relation between K.E. and Total Energy?
$ K.E.=-E $Q4. What is Binding Energy?
The minimum energy required to move a satellite from its orbit to infinity.
$ B.E.=\frac{GMm}{2r} $Q5. What happens if the kinetic energy is doubled?
The total energy becomes zero and the satellite escapes from Earth's gravitational field.
Q6. On what factors does Binding Energy depend?
- Mass of Earth ($M$)
- Mass of satellite ($m$)
- Orbital radius ($r$)
Quiz (MCQs)
-
The total energy of an orbiting satellite is:
A. Positive
B. Zero
C. Negative
D. Infinite
Answer: C. Negative -
The kinetic energy of a satellite is:
A. $U$
B. $-U$
C. $-\frac{U}{2}$
D. $\frac{U}{2}$
Answer: C -
Binding energy of a satellite is:
A. $\frac{GMm}{r}$
B. $\frac{GMm}{2r}$
C. $\frac{GMm}{4r}$
D. $\frac{2GMm}{r}$
Answer: B -
If total energy becomes zero, the satellite will:
A. Continue in orbit
B. Fall towards Earth
C. Escape from Earth
D. Stop moving
Answer: C -
SI unit of binding energy is:
A. Watt
B. Newton
C. Joule
D. Pascal
Answer: C
Quick Revision Formulae
$$ K.E.=\frac{GMm}{2r} $$Conclusion: A satellite remains in orbit because its total energy is negative, and the minimum energy required to free it from Earth's gravitational field is called its binding energy.
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