Param Himalaya - परम हिमालय

NCERT Solution Class 11 Physics Chapter 3 Motion in a plane  - Param Himalaya 3.1 State, for each of the following physical quantities, if it is a scalar or a vector : volume, mass, speed, acceleration, density, number of moles, velocity, angular frequency, displacement, angular velocity . Solution   :  Scalars : Volume, mass , speed , density, number of moles , angular frequency. Vectors : Acceleration, velocity, displacement, angular velocity. 3.2 Pick out the two scalar quantities in the following list : force, angular momentum, work, current, linear momentum, electric field, average velocity, magnetic moment, relative velocity. Solution :  The dot product of force and displacement is the work done. Work is scalar quantity since the dot product of two quantities is always scalar. Current is a scalar quantity as it is described only by its magnitude and it is independent of direction. 3.3 Pick out the only vector quantity in the following list :Temperature, pressur...

सरस्वती वंदना -  हे हंसवाहिनी ज्ञानदायिनी अम्ब विमल मति दे - Saraswati vandana hey Hans vahini gyan dayini lyrics हे हंसवाहिनी ज्ञानदायिनी अम्ब विमल मति दे। अम्ब विमल मति दे॥ जग सिरमौर बनाएं भारत, वह बल विक्रम दे। वह बल विक्रम दे॥ हे हंसवाहिनी ज्ञानदायिनी अम्ब विमल मति दे। अम्ब विमल मति दे॥ साहस शील हृदय में भर दे, जीवन त्याग-तपोमय कर दे, संयम सत्य स्नेह का वर दे, स्वाभिमान भर दे। स्वाभिमान भर दे॥1 हे हंसवाहिनी ज्ञानदायिनी अम्ब विमल मति दे। अम्ब विमल मति दे॥ लव, कुश, ध्रुव, प्रहलाद बनें हम मानवता का त्रास हरें हम, सीता, सावित्री, दुर्गा मां, फिर घर-घर भर दे॥2 हे हंसवाहिनी ज्ञानदायिनी अम्ब विमल मति दे। अम्ब विमल मति दे॥

NCERT Solutions for Class 11 Physics Chapter 12 Kinetic Theory  - Param Himalaya  12.1 Estimate the fraction of molecular volume to the actual volume occupied by oxygen gas at STP. Take the diameter of an oxygen molecule to be 3 Å. Solution :  1. Calculate the volume of a single oxygen molecule: Assuming an oxygen molecule is spherical, its volume ($V_{\text{molecule}}$) can be calculated using the formula for the volume of a sphere: $$V_{\text{molecule}} = \frac{4}{3} \pi r^3$$ where $r$ is the radius of the oxygen molecule. The diameter is given as 3 Å, so the radius is  $r = \frac{3}{2} \text{ Å} = 1.5 \times 10^{-10} \text{ m}$ Plugging in the value: $V_{\text{molecule}} = \frac{4}{3} \pi (1.5 \times 10^{-10} \text{ m})^3$ $V_{\text{molecule}} = \frac{4}{3} \pi (3.375 \times 10^{-30}) \text{ m}^3$ $V_{\text{molecule}} \approx 1.414 \times 10^{-29} \text{ m}^3$ 2. Calculate the total volume occupied by one mole of oxygen molecules: One mole of any substance contai...

Lyrics : देश हमें देता है सब कुछ, हम भी तो कुछ देना सीखें- desh hame deta h sb kuch hum bhi to kuch dena sikhe - Param Himalaya  देश हमें देता है सब कुछ, हम भी तो कुछ देना सीखें ॥धृ॥ सूरज हमें रौशनी देता, हवा नया जीवन देती है ।  भूख मिटने को हम सबकी, धरती पर होती खेती है । औरों का भी हित हो जिसमें, हम ऐसा कुछ करना सीखें ॥१॥ गरमी की तपती दुपहर में, पेड़ सदा देते हैं छाया । सुमन सुगंध सदा देते हैं, हम सबको फूलों की माला । त्यागी तरुओं के जीवन से, हम परहित कुछ करना सीखें ॥२॥ जो अनपढ़ हैं उन्हें पढ़ाएँ , जो चुप हैं उनको वाणी दें । पिछड़ गए जो उन्हें बढ़ाएँ, समरसता का भाव जगा दें । हम मेहनत के दीप जलाकर, नया उजाला करना सीखें ॥३॥

Ncert Solutions Class 9 Science Chapter 10 Work and Energy - Param Himalaya  Example 10.1 A force of 5 N is acting on an object. The object is displaced through 2 m in the direction of the force (Fig. 10.2). If the force acts on the object all through the displacement, then work done is ? Solution: Given Force = 5N , Displacement = 2m Work = Force × Displacement  W = 5 N × 2 m =10 N m or 10 J.  Page 115 1. A force of 7 N acts on an object.The displacement is, say 8 m, in the direction of the force (Fig. 10.3). Let us take it that the force acts on the object through the displacement. What is the work done in this case? Solution : Work done = Force × displacement W = F × S W = 7 × 8 W= 56 J Example 10.2 A porter lifts a luggage of 15 kg from the ground and puts it on his head 1.5 m above the ground.Calculate the work done by him on the luggage. Solution: Work done = F × s = mg × s W= 15 kg × $10 m s^{-2}$ × 1.5m W=225 $kgms^{-2}$ Page 116 1. When do we say that work is don...